△ABC is right angled at A. AD is perpendicular to BC. If AB = 5cm, BC = 13cm and AC = 12cm. Find the area of \triangle△ ABC. Also find the Length of AD.
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In right angles triangle BAC, AB=5cm and AC=12cm
In right angles triangle BAC, AB=5cm and AC=12cmArea of triangle= 2/1×base×height= 2/1×AB×AC
= 2/1 ×5×12=30cm
Now, in ΔABC,Area of triangle ABC= 2/1×BC×AD⇒30= 2/1 ×13×AD
AD=30×2/13= 60/30 cm.
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