∆ABC is right angled at A and AD ┴ BC, divides BC such that AD2
=
BD.CD.If AD= 4 cm and BD =2 cm, Find BC.
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Answer:
In triangle ABC , AD is perpendicular to BC and AD² = BD.DC To prove : BAC = 90° Proof : in right triangles ∆ADB and ∆ADC So
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