Question

ΔABC is right angled at A and AD is perpendicular to BC. If BC= 13 cm and AC = 5 cm, the ratio of the areas of ΔABC and ΔADC is

(1) 25 : 169 (2) 169 : 25 (3) 5 : 13 (4) 13 : 5

Answer 1

Answer:

2

Step-by-step explanation:

in ∆ABC and ∆ADC, we have:

∠BAC = ∠ADC = 900  

∠ACB = ∠ACD

By AA similarity, we can conclude that ∆ BAC~ ∆ ADC.  

Hence, the ratio of the areas of these triangles is equal to the ratio of squares of their corresponding sides.

n ∆ABC and ∆ADC, we have:

∠BAC = ∠ADC = 900  

∠ACB = ∠ACD

By AA similarity, we can conclude that ∆ BAC~ ∆ ADC.  

Hence, the ratio of the areas of these triangles is equal to the ratio of squares of their corresponding sides.

solution of this

Hence, the ratio of areas of both the triangles is 169:25

Answer 2

Answer:

169:25

Step-by-step explanation: