Question

ΔABC is right angled at A (Fig 11.25). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ΔABC. Also find the length of AD.


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Answer 1

Answer:

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Step-by-step explanation:

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.

Answer 2

Answer:

In right angled triangle BAC, AB = 5 cm, BC = 13 cm and AC = 12 cm.

Area of triangle BAC = 1/2 × Base × Height

= 1/2 × 5 cm × 12 cm

= 30 cm2

Area of triangle ABC = 1/2 × Base × Height 

Now BC = 13 cm

30 cm2 = 1/2 × 13 cm × AD

AD = (30 cm2 × 2) / 13 cm

AD = 60 cm2 / 13 cm

AD = 4.61 cm

Step-by-step explanation:

I hope it helped you!