∆ABC is right angled at A.find the value of tan B X tan C. class 10
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tanB = CA/AB...
tanC = AB/CA...
tanB × tanC = CA×AB/AB×CA
tanB×tanC = 1
_* hope it helps *_
tanC = AB/CA...
tanB × tanC = CA×AB/AB×CA
tanB×tanC = 1
_* hope it helps *_
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