∆ ABC is right-angled at A (in Figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ ABC. Also find the length of AD.
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Answered by
9
Solution:
In right angled triangle BAC, AB = 5 cm, BC = 13 cm and AC = 12 cm.
Area of triangle BAC = 1/2 × Base × Height
= 1/2 × 5 cm × 12 cm
= 30 cm2
Area of triangle ABC = 1/2 × Base × Height
Now BC = 13 cm
30 cm2 = 1/2 × 13 cm × AD
AD = (30 cm2 × 2) / 13 cm
AD = 60 cm2 / 13 cm
AD = 4.61 cm
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Answered by
10
Answer:
60/13 cm
Step-by-step explanation:
Area of ∆ ABC
= 1/2 (base × height)
= 1/2 (AB × AC) = 1/2 (5×12)
= 30cm²
Hence, the area of ∆ ABC is 30 cm².
Again, Area of ∆ ABC
= 1/2 (base × height)
= 1/2 (BC × AD)
30= 1/2 (13×AD)
13×AD = 30×2
AD = 30×2 /13 = 60/13 cm
Hence, the length of AD is 60/13 cm.
hope it helps you.
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