Question

ΔABC is right angled at B and BD⊥AC. If AD = 4 cm & CD = 5 cm, then find BD & AB.

Answer with the diagram. Points: 10

Answer 1

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Answer 2

Hi ,

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In a right angled Triangle ABC the

altitude BD on the hypotenuse AC

is the mean proportional between

the segments ( AD , DC ) cut off

on the hypotenuse by the altitude.

BD² = AD × DC

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According to the problem given ,

AD = 4 , CD = 5 ,

BD² = AD × DC

= 4 × 5

BD = √20

BD = 2√5

And ,

In Triangle ADB , angle ADB = 90°

AB² = AD² + BD²

= 4² + 5²

AD² = 36

AD = √36 = 6

I hope this helps you.

:)