ΔABC is right angled at B, BC = 7 cm and AC – AB = 1 cm. Find the value of cos A + sin A.
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ac-ab=1cm ac= 1+abby Pythagoras Theoremac^2=ab^2+bc^2(1+ab)^2=ab^2 +(7)^21+ab^2+2ab= ab^2+49ab^2-ab^ ... More
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