∆abc is right angled at b. bd is an altitude. if ad = 50 cm and dc = 8 cm what is the value of bd (in cm)?
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triangle ABC is a right angle triangle
angle ADB is similar to triangle bdc by using theorem
ad/bd= bd/bc
bd^2= ad*dc
bd^2=50*8
bd=20cm
angle ADB is similar to triangle bdc by using theorem
ad/bd= bd/bc
bd^2= ad*dc
bd^2=50*8
bd=20cm
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