ABC is right angled at 'B'. If AC = 13 cm & BC = 5 cm. What is the Perimeter of the below given shape?
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Answer:
The answer is 17 cm
Step-by-step explanation:
The lenth of BC is root (13 square-5 Square) =ROot144 =12 cm
If The line from M drawn to P point in AB and to the point QIn BC
Then MP=1/2 of BC =6 cm
As the same way MQ=1/2AB =5/2cm
Now the perimmeter of BPMQ is 5/2+5/2+6+6=17 cm
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Answered by
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Question :-
ABC is right angled at 'B'. If AC = 13 cm & BC = 5 cm. What is the Perimeter of the below given shape?
Answer :-
Hypotenuse² = Perpendicular² + Base²
13² = 5² + Base²
169 - 25 = Base²
√144 = Base
12 = Base
Perimeter = a+b+c
12 + 13 + 5
30 cm
Step-by-step explanation:
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