Question

∆ABC is right angled at B. If m∠C = 450, then find the value of (cosecA - √3).​

Answer 1

Solution

In Δ ABC

 ∠B=90°

m ∠C=45°

Sum of three angles of triangle is 180°.

∠A + ∠B+∠C=180°

∠A+90°+45°=180°

∠A=180°-135°

∠A=45°

⇒Cosec A - √3

= Cosec 45° - √3

= √2 - √3