ABC is right-angled at B such that BC = 6 cm and AB = 8 cm. Find the radius of its
incircle.
Answers
Answer:
2
Step-by-step explanation:
Our aim is to find the radius of its in-circle.
We know that ABC is a right angled triangle, and we also know that BC is equal to 6cm and AB is equal to 8cm.
In order to find AC, we will use Pythagoras theorem.
>> AB^2 + BC^2 = AC^2
From this we can conclude that AC = 10 cm.
Then, we can draw an in-circle as is shown in the picture bellow.
Now, in order to get our radius we have that AC= 8 - x + 6 - x , this means that AC = 14 - 2x .
We already know that AC is equal to 10 cm, then 14 - 2x = 10 , this means that 2x = 4 which is equivalent to say that x = 2 cm.
Hence, the radius of the in-circle of the triangle ABC is equal to 2 cm.
I hope this helps your studies!! Keep it up!
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
Our aim is to find the radius of its in-circle.
We know that ABC is a right angled triangle, and we also know that BC is equal to 6cm and AB is equal to 8cm.
In order to find AC, we will use Pythagoras theorem.
>> AB^2 + BC^2 = AC^2
From this we can conclude that AC = 10 cm.
Then, we can draw an in-circle as is shown in the picture bellow.
Now, in order to get our radius we have that AC= 8 - x + 6 - x
, this means that AC = 14 - 2x
.
We already know that AC is equal to 10 cm, then 14 - 2x = 10
, this means that 2x = 4 which is equivalent to say that x = 2 cm.
Hence, the radius of the in-circle of the triangle ABC is equal to 2 cm.
I hope this helps your studies!! Keep it up!