Question

∆
ABC is right-angled triangle at A. AD is perpendicular to BC. If AB = 5 cm, BC
=13 cm, and AC = 12 cm, find the area of ∆ABC. Also, find the length of AD.​

Answer 1

Area of triangle is 30 cm²

Answer 2

Area of right triangle ABC

=\frac{1}{2}\times AB\times AC=\frac{1}{2}\times5\times12=30cm^2=

2

1

×AB×AC=

2

1

×5×12=30cm

2

Area of \triangle ABC=\frac{1}{2}\times BC\times AD△ABC=

2

1

×BC×AD

30cm^2=\frac{1}{2}\times13cm\times AD30cm

2

=

2

1

×13cm×AD

AD=\frac{30\times2}{13}cmAD=

13

30×2

cm

=\frac{60}{13}cm=4.62cm=

13

60

cm=4.62cm