Question

Abc is right angled triangle where angle b is 90°and ab=8 cm and bc=6 cm find diameter of circle inscribed in the triangle

Answer 1

Answer:

Step-by-step explanation:

IF A CIRCLE INSCRIBED  A RIGHT ANGLED TRIANGLE  

THEN THE DIAMETER IS HYPOTENUSE

AC =$\sqrt{AB^2+BC^2} =\sqrt{8^2+6^2}=\sqrt{64+36} =\sqrt{100} =10$  cm

DIAMETER = 10 cm

Answer 2

$ac = \sqrt{ {ab}^{2} + {bc}^{2} } \\ \\ = \geqslant ac = \sqrt{ {8}^{2} + {6}^{2} } \\ \\ = \geqslant ac = \sqrt{64 + 36} \\ \\ = \geqslant ac = \sqrt{100} \\ \\ = \geqslant ac = 10$