∆ ABC is right angledtriangle in which ∠A = 90⁰ and AB = AC . Find ∠B and∠C.
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Answer:
the angle will be of 45 and 45
Answered by
1
Answer:
Since AB=AC,
So, △ABC is Right-angled isosceles.
∠B=∠C ...(angles opp. to equal sides are equal)
∠A+∠B+∠C=180°
...(angle - sum property of a triangle)
Substituting ∠B=∠C, ∠A=90°
90° +2∠B=180°
2∠B=180° –90°= 90°
∘
⇒∠B=45°
So, ∠C=∠B=45°
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