ABC IS RIGHT TRIANGLE ANGLE B IS 90 DEGERE . P AND Q ARE MP OF AB AND BC . PROVE THAT.
1. 4PC SQUARE=4BC SQUARE + AB SQUARE
2.4PA SQUARE=4AB SQUARE+ BC SQUARE
3. 4PC SQUARE + 4 PQ SQUARE= 5AC SQUARE
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Join c and p to form cp
In ΔBPC , angle b = 90⁰
by pythagoras theorem
⇒⇒[tex]PC^2=PB^2+BC^2 \\ =( \frac{AB}{2})^2 +BC^2 \\ = \frac{AB^2}{4} +BC^2 \\ AB^2+4BC^2=4CP^2 [/tex]
In ΔBPC , angle b = 90⁰
by pythagoras theorem
⇒⇒[tex]PC^2=PB^2+BC^2 \\ =( \frac{AB}{2})^2 +BC^2 \\ = \frac{AB^2}{4} +BC^2 \\ AB^2+4BC^2=4CP^2 [/tex]
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