Question

ABC is right triangle right angled at B, in which AB=40units and AC=41units. Find tan^2C-cot^2A​

Answer 1

Answer:

0

Step-by-step explanation:

In right angled triangle ABC

Given

B = 90 deg

=> A + C = 90 deg

=> A = 90 deg - C

WKT

$if \: \alpha + \beta = {90}^{0}$

$tan \: \alpha = cot \: ( {90}^{0} - \alpha )$

Now

${ \tan }^{2} C - { \cot}^{2} A$

$= tan^2C - cot^2(90^0-C)$

$= tan^2C - tan^2C$

$= 0$

Hope it helps