Question

ABC is
sides
triangle in which altitudes BE and cf
to sides AC
and
AB are equal show that
Triangle ABE = TRIANGLE ACF
AB = AC
ABC IS AN ISOSCELES TRIANGLE​

Answer 1

Answer:

yes ABC is an isosceles triangle

Step-by-step explanation:

given ABC is triangle

AB=AC two sides are equal

so, it is isosceles

Answer 2

(i) In ΔABE and ΔACF, ∠ABE and ∠ACF (Each 90º) ∠A = ∠A (Common angle) BE = CF (Given) ∴ ΔABE ≅ ΔACF (By AAS congruence rule) (ii) It has already been proved that ΔABE ≅ ΔACF ∴ AB = AC