Math, asked by omprakashsahni619, 1 year ago

ΔABC is similar to ΔDEF The area of ΔABC is 100cm^2 and the area of ΔDEF is 49 cm^2 If the altitude of ΔABC is 5 cm then the corresponding altitude of ΔDEF is​

Answers

Answered by kartik2507
1

Step-by-step explanation:

in two similar triangle the ratio of the square of the altitude is equal to the ratio of their corresponding areas

 \frac{ {5}^{2} }{ {x}^{2} }  =  \frac{100}{49}  \\  {x}^{2}  \times 100 = 25 \times 49 \\  {x}^{2}  =  \frac{25 \times 49}{100}  \\  {x}^{2}  =  \frac{1225}{100}  \\ x =  \sqrt{ \frac{1225}{100} }  \\ x =  \frac{35}{10}  \\ x = 3.5cm

the altitude of ∆DEF = 3.5 cm

hope you get your answer

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