Question

∆ABC is sin C=3/5 then find cosA​

Answer 1

Answer:

ANSWER

Given:sinA=hypotenuseoppositeside=53

⇒adjacentside=(hypotenuse)2−(oppositeside)2

=52−32=25−9=16=4

⇒cosA=hypotenuseadjacentside=54

∴sinA=53,cosA=54

Given:sinB=hypotenuseoppositeside=135

⇒adjacentside=(hypotenuse)2−(oppositesi

Step-by-step explanation:

I hope this will help you...

I helped you know please help me ...

follow , thank and mark as brainliest...

please

Answer 2

Answer:

given

sinC=3/5

then sinc=opposite side to A/hypotenuse

CosA=3/5