ΔABC is such that AB=3 cm, BC= 2cm, CA= 2.5 cm. If ΔABC ~ ΔDEF and EF = 4cm, then perimeter of ΔDEF is
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Answer:
15
Step-by-step explanation:
In ABC
AB = 3 cm
BC = 2 cm
AC = 2.5 cm
perimeterof triangle = sum of all sides =3+2+2.5 = 7.5 cm
Triangle DEF is similar to triangle ABC
corresponding side of EF in triangle ABC is BC = 2 cm
Theorem: The ratio of the side of similar triangle is equal to the ratio of the perimeter of corresponding triangle
so, let the perimeter of triangle DEF be x
so, 4/5 = x/ 7.5
4 x 7.5 /2 = x
15 =x
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