∆ABC is such that AB=3 cm, BC= 2cm, CA= 2.5 cm. If ∆ABC ~ ∆DEF and EF = 4cm, then perimeter of ∆DEF is
(a) 7.5 cm
(b) 15 cm
(c) 22.5 cm
(d) 30 cm
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Triangle DEF = 15cm is the answer
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