∆ ABC is such that AB=3 m, B C = 2m and CA = 2.5 cm
If ADEF ~ ∆ ABC
and EF = 4cm then perimeters of
ADEF is ?
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4
Answer:
15
Step-by-step explanation:
given ∆ ABC ~ ∆ DEF , AB = 3, BC = 2 & EF = 4 cm
BC/EF = CA/DF
2/4 = 2.5/ DF => DF = 5 cm
similarly
AB /DE = AC/DF
3/ DE = 2.5/ 5 => DE = 6 cm
perimeter of DEF = DE + EF + DF
= 6 + 4 + 5 = 15 cm
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