Question

ABC is the equilateral triangle and CD of the right angle triangle BCD is 8 cm.find the side of the equilateral triangle and find BD​

Answer 1

Step-by-step explanation:

From figure: Area of shaded region = Area of ABC – Area of DBC …..(1) Area of △ABC: Area = √3/4 (side)2 = √3/4 (10)2 = 43.30 So area of △ABC is 43.30 cm2 Area of right △DBC: Area = 1/2 x base x height …(2) From Pythagorean Theorem: Hypotenuse2 = Base2 + Height2 BC2 = DB2 + Height2 100 – 64 = Height2 36 = Height2 or Height = 6 equation (2) => Area = 1/2 x 8 x 6 = 24 So area of △DBC is 24 cm2 Equation (1) implies Area of shaded region = 43.30 – 24 = 19.30 Therefore, Area of shaded region = 19.3 cm2

Answer 2

Answer:

hi im yusuf can we talk bolo