Question

ABC is triangle. Angle B is 90 degree. bm is median. AB is 15 and BM is 12.5 find BC.

Answer 1

Let ABC a triangle.
Angle B = 90
bm is median
Therefore m lies btw AC.
Therefore Am=Cm

Now,
In triangle ABm

bm = 12.5

ab^2 = bm^2 + am^2
am^2 = ab^2 - bm^2
=225 - 156.25
=68.75

Therefore
am = sqrt of 68.75
am = 8.29

AC = 2*am
=16.58

In triangle ABC,
ab^2 + bc^2 = ac^2
bc^2 = ac^2 - ab^2

bc^2 = (16.58)^2 - (15)^2
= 274.89 - 225
= 49.89

Therefore
BC = sqrt of 49.89
= 7.06

BC = 7.06