Abc is triangle right angle at c if ab=25cm and ac = 7cm find bce
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Answer:
Given: PQ = 10 cm, PR = 24 cm
Let QR be xx cm.
In right angled triangle QPR,

(Hypotenuse)2= (Base)2+ (Perpendicular)2(Hypotenuse)2= (Base)2+ (Perpendicular)2
[By Pythagoras theorem]
⇒⇒ (QR)2= (PQ)2+ (PR)2(QR)2= (PQ)2+ (PR)2
⇒⇒ x2=(10)2+(24)2x2=(10)2+(24)2
⇒⇒ x2x2 = 100 + 576 = 676
⇒⇒ x=676−−−√x=676 = 26 cm
Thus, the length of QR is 26 cm.
Given: PQ = 10 cm, PR = 24 cm
Let QR be xx cm.
In right angled triangle QPR,

(Hypotenuse)2= (Base)2+ (Perpendicular)2(Hypotenuse)2= (Base)2+ (Perpendicular)2
[By Pythagoras theorem]
⇒⇒ (QR)2= (PQ)2+ (PR)2(QR)2= (PQ)2+ (PR)2
⇒⇒ x2=(10)2+(24)2x2=(10)2+(24)2
⇒⇒ x2x2 = 100 + 576 = 676
⇒⇒ x=676−−−√x=676 = 26 cm
Thus, the length of QR is 26 cm.
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