Question

∆ ABC~∆LBN. In ∆ABC, AB=5.1, angle B=40°, BC=4.8 cm. construct ∆ABC and ∆LBN such that AC/LN=4/7. please give me your number​

Answer 1

Answer:

Answer

Given:

ΔABC∼ΔLBN.

In ΔABC,AB=5.1cm

∠B=40

0

,BC=4.8cm,

LN

AC

=

7

4

Let

steps for constructing ΔABC∼ΔLBN

Step-1: Draw ΔABC such that AB=5.1cm

∠B=40,BC=4.8cm

Step-2: Divide segment BC into 4 equal parts

Step-3: Make point Non ray BC such that length of BN is seven times of each part of segment BC.

Step-4: Draw a line parallel to side AC, through N. Name the point where the parallel line intersects ray BA as 1

Hence, here ΔABC∼ΔLBN

Answer 2

Answer:

∆ABC~∆LBN

this means that they are equiangular

angle BLN= Angle BAC

but they form a pair of alternative interior angles

thus , LN || AC

hence AC/LN= 4/7