∆ABC में A= 90° है, BP और CQ दो
मध्यस्थ हैं तो BP^2+CQ ^2का मान है?
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Step-by-step explanation:
BC² = AB² + AC²
BC² = (2CQ)² + (2BP)²
4(BP²+CQ²) = BC²
BP² + CQ² = BC²/4
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