Question

∆ABC मे जिसका कोण समकोण है ,AB=24cm and BC=7cm है निम्नलिखित का मान ज्ञात कीजिये
1) sin A, cos A

Answer 1

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English Version of the Given Question :-

In ΔABC , right -angled at B , AB = 24 cm , BC = 7 cm , Determine :

(i) Sin A , Cos A

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Step :- 1

By Pythagoras Theorem ,

$AC^2 = AB^2 + BC^2$

⇒ $(24)^2 + (7)^{2} = 625$

⇒ $AC = \sqrt{625}$

⇒ 25 cm

Step :- 2

(i) $SinA=\frac{BC}{AC}$

⇒ $\frac{7}{25}$

(ii) $CosA = \frac{AB}{AC}$

⇒ $\frac{24}{25}$

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Answer 2

Step-by-step explanation:

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