∆ABC me DE|| BC tatha AD=3 cm, DB=5 cm, AE=6 cm, hai to EC ka man gyat lijiye
Answers
Given : ∆ABC me DE|| BC tatha AD=3 cm, DB=5 cm, AE=6 cm,
To find : EC
Solution:
∆ABC me DE|| BC
a line drawn in a triangle parallel to one side intersect other other two sides in same ratio
Hence AD/DB = AE/EC
AD = 3 cm
DB = 5 cm
AE = 6 cm
EC = x cm
3/5 = 6 /x
cross multiplying
=> 3 * x = 6 * 5
=> 3x = 30
Dividing both sides by 3
=> x = 10 cm
EC = 10 cm
Learn more:
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Answer:
Given : ∆ABC me DE|| BC tatha AD=3 cm, DB=5 cm, AE=6 cm,
To find : EC
Solution:
∆ABC me DE|| BC
a line drawn in a triangle parallel to one side intersect other other two sides in same ratio
Hence AD/DB = AE/EC
AD = 3 cm
DB = 5 cm
AE = 6 cm
EC = x cm
3/5 = 6 /x
cross multiplying
=> 3 * x = 6 * 5
=> 3x = 30
Dividing both sides by 3
=> x = 10 cm
EC = 10 cm
Learn more:
In the given figure, If DE || BC and AD : DB = 1:2 then Area of ∆ADE ...
https://brainly.in/question/17155687
In the given figure, AD = 1.28 cm, DB = 2.56cm AE = 0.64 cm. DE will ...
https://brainly.in/question/13953131