∆ABC~∆MNP , BC:NP=3:5 then A(∆ABC)/A(∆MNP)=.......
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SinceM,N,andParethemid−pointsofAB,ACandBCrespectively.
HenceMN=
2
1
BC
⟹BC=2MN
⟹BC=2×3=6cm
SimilarlyAC=2MP=2×2.5=5cm
andAB=2NP=2×3.5=7cm
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