∆ABC~∆POR.A(∆ABC)=9:16. find BC:OR
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3:4
Step-by-step explanation:
Theorem,
if ∆ABC ~ ∆POR then,
ar(∆ABC):ar(∆POR) = (BC)²:(OR)²
NOW,
9:16 = (BC)²:(OR)²
Taking square roots on both sides,
3:4 = BC:OR
or,
BC:OR = 3:4
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