Question

∆ABC~∆POR, If AB: PQ-4:5, find
A(∆ABC) : A(∆POR)​

Answer 1

Answer:

16/25

Step-by-step explanation:

according to theorem of area of similar triangles

A(∆ABC). AB^2

_______ = ___

A(∆PQR). PQ^2

= 4^2/5^2

=16/25

Hope its helpful, pls thank:)

Answer 2

• जर ∆ABC ~∆PQR, PQ=4:5 आणि A(∆PQR)=125° असेल, तर A(ABC) काढा