∆ABC ~ ∆PQR,
9×A(∆PQR) = 25 ×A(∆ ABC).
If QR = 30, then find BC.
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1
arc(△PQR)
arc(△ABC)
=
QR
2
BC
2
⇒
49
25
=
(9.8)
2
BC
2
⇒
7
5
=
9.8
BC
⇒BC=
7
9.8×5
=7.0cm
2
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