Question

.∆ ABC ~ ∆ PQR, 9 x A (∆ PQR) = 16 x A (∆ ABC) If QR = 20 then find BC.​

Answer 1

Answer:

Given:

∆LMN ~ ∆PQR

9 × A (∆PQR ) = 16 × A (∆LMN)

Consider, 9 × A (∆PQR ) = 16 × A (∆LMN)

A(ΔLMN)A(ΔPQR)=916⇒MN2QR2=3242⇒MNQR=34

⇒MN=34×QR⇒MN=34×20                  [∵QR=20]⇒MN=15

mn la bc kar vedaa

ani lmn la abc

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