Question

∆ABC ~∆PQR , A (ABC) = 16
A(PQR)= 25 then find the value of
ratio AB\PQ​

Answer 1

∆ABC ~∆PQR

by theorem of similar triangles,

A(ABC)= AB²

A(PQR)= PQ²

16 = AB²

25 PQ²

by taking square root,

4 =AB

5 PQ

AB = 4

PQ = 5