∆ABC ~ ∆ PQR , A (∆ABC) = 36 , A (∆PQP) = 64, if PQ= 16 find AB
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Answer:
AB=12
Step-by-step explanation:
{ar(ABC)/ar(PQR) }=AB^2/PQ^2
36/64=AB^2/16^2
36/64=AB^2/256
(36×256)/64=AB^2
144=AB^2
AB=12
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