∆ABC∆PQR. A(∆ABC) = 49 cm2
and A(∆PQR) = 121 cm2
. If BC = 10·5 cm,
find QR.
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Answer:
Answer
We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding sides.
∴
ar(ΔPQR)
ar(ΔABC)
=
QR
2
BC
2
⇒
121
64
=
(15.4)
2
BC
2
⇒
11
8
=
15.4
BC
⇒BC=
11
8×15.4
=11.2cm
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