Math, asked by Diyacharlotte721, 9 months ago

∆ABC~∆PQR, AB=6,BC=4,AC=8,PR=6 then find PQ+QR

Answers

Answered by charithgnt
2

Answer:

12.

Step-by-step explanation:

Given that

Δ ABC is similar to Δ PQR.

AB = 6, BC = 4, AC = 8, PR = 6.

according to problem,

AB = PR

BC = PQ

AC = QR

it is given to find the value of PQ + QR

then,

BC + AC = PQ + QR

4 + 8 = PQ + QR

PQ + QR = 12

∴ PQ + QR = 12

HOPE THIS HELPS YOU COMRADE

Answered by gjenagjena66
1

Answer:

7.5 \: units

Step-by-step explanation:

By Basic proportionality theorem,

AC/PR=AB/PQ=BC/QR

8/6=6/PQ

PQ=4.5

8/6=4/QR

QR=3

PQ+QR= 4.5 + 3 = 7.5 units

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