abc~pqr and 2×a(abc)=3×a(pqr) then =a(∆pqr)÷a(∆abc)
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abc~pqr and 2×a(abc)=3×a(pqr) then =a(∆pqr)÷a(∆abc) =2/3 may be
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abc~pqr and 2×a(abc)=3×a(pqr) then
By solving this equation,
=2/3 Ans
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