∆abc~∆pqr angle a =50, angle b=100° find angle r
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Answer:
given :-
angle A = 50°
angle B = 100°
to find :-
angle R = ?
solution :-
A+ B + R = 180° ( angle sum property of triangle)
50° + 100° + R = 180°
150° + R = 180°
R = 180° - 150°
R = 30°
answer :-
R = 30°
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