∆ABC ~ ∆pQR, areas of ∆ABC and ∆PQR are 64cm² and 100cm² respectively.if BC=4cm then find QR
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area Triangle ABC / area of Triangle PQR = BC²/QR²
= 64/100 = BC/QR
= 8/10 = 4 / QR
= QR = 40/8 = 5 CM
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