Question

∆ABC ~ ∆PQR, IF AB = 5, PQ = 10, then find the value of
A (∆ABC):A (∆PQR)
​

Answer 1

Answer:

1:2

Step-by-step explanation:

As ΔABC~ΔPQR

AB/PQ =BC/QR = AC/PR

5/10 = BC/QR = AC/PQ

ΔABC/ΔPQR=1/2 =BC/QR=AC/PR

Answer 2

Answer:-

Yiur Answer is 1:4.

Explanation:-

Given:-

• $\tt\triangle ABC\sim\triangle PQR.$

• AB = 5.

• PQ = 10.

To Find:-

• $\tt A(\triangle ABC) : A(\triangle PQR).$

Formula Used:-

$\\ \large\purple{\longrightarrow\boxed{\orange{\bf A \ratio a = (S\ratio s)^2.}}}$

Where,

• A : a is ratio of areas of two similar triangles.

• S : s is the ratio of any two corresponding sides of the similar triangles.

So Here,

• A : a = ?? [To Find].

• $\tt S\ratio s = 5\ratio 10 =1\ratio 2.$

Now,

By using formula we get

$\\ \bf\mapsto A \ratio a = (S\ratio s)^2.$

$\\ \tt\mapsto A(\triangle ABC) \ratio A(\triangle PQR) = (1\ratio 2)^2.$

$\\ \tt\mapsto A(\triangle ABC) \ratio A(\triangle PQR) =(1 \times 1) \ratio(2 \times 2).$

$\\ \red{\mapsto \boxed{ \blue{ \bf A(\triangle ABC) \ratio A(\triangle PQR) =1 \ratio4.}}}$

Therefore Area of triangle ABC : Area of triangle PQR = 1:4.