∆ABC~∆PQR. If AM and PN are altitudes of ∆ABC and ∆PQR respectively and AB2
:
PQ2 = 4 : 9, then AM:PN
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Given:
∆ABC~∆PQR. If AM and PN are altitudes of ∆ABC and ∆PQR respectively and AB2
Since ratio of similar triangles are in ratio of squares of their corresponding sides
ar(∆ABC)/ ar(∆PQR) = (AB/PQ)² = 4/9
Also, ratio of similar triangles are in ratio of squares of their corresponding altitudes.
(AM/PN)² = 4/9
AM/PN = 2/3R
Hence the answer is 2:3
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