Math, asked by sampadaparab1980, 5 months ago

∆ ABC ~ ∆ PQR, in ∆ ABC, AB = 5.4 cm, BC = 4.2 cm, AC = 6.0 cm. AB : PQ = 3 : 2. Find all sides of ∆ PQR.

Answers

Answered by ashmaanshetty
31

Answer:

PQ = 3.6 cm, QR = 2.8 cm, PR = 4cm

Step-by-step explanation:

∆ ABC ~ ∆ PQR,

∴Their corresponding sides are similiar.

AB/PQ = BC/QR = AC/PR = 3/2

∴5.4/PQ = 4.2/QR = 6/PR= 3/2

∴PQ = 3.6 cm

∴ QR = 2.8 cm, PR = 4cm.

Please mark as BRAINLIEST!!!

Answered by amitnrw
10

Given : ∆ ABC ~ ∆ PQR,

in ∆ ABC,  AB = 5.4 cm, BC = 4.2 cm, AC = 6.0 cm.

AB : PQ = 3 : 2.

To Find :  all sides of ∆ PQR.

Solution:

∆ ABC ~ ∆ PQR

Corresponding sides of similar triangle are proportional

Hence

AB/PQ = AC/PR = BC/QR

AB : PQ = 3 : 2.

=> AB/PQ = 3/2

Hence

AB/PQ = AC/PR = BC/QR = 3/2

AB = 5.4 cm, BC = 4.2 cm, AC = 6.0 cm

=> 5.4/PQ = 6.0 /PR = 4.2/QR = 3/2

=> PQ = 3.6 cm

   QR = 2.8 cm

   PR = 4 cm

All sides of ∆ PQR are

PQ = 3.6 cm ,     QR = 2.8 cm and PR = 4 cm  

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