Question

∆ABC ~ ∆PQR , QR = 1.6cm , BC = 2.4 cm, Find A(∆ABC ) ∶A(∆PQR )​

Answer 1

Hence

QC

AQ

=

PB

AP

3

2

=

PB

2.4

PB=3.6cm

AB=AP+PB=2.4+3.6=6cm

As PQ∥BC

∠AQP=∠ACB

∠APQ=∠ABC

So by AAA △AQP∼△ACB

Hence

AC

AQ

=

CB

QP

5

2

=

6

QP

QP=2.4cm

So AB=6cm and QP=2.4cm