Question

∆ ABC ~ ∆ PQR such that ∠A = ∠P and ∠B = ∠Q. If AB = 2 m and PQ = 20 cm,
Area (ΔABC)/Area (ΔPQR) ​

Answer 1

∠P = ∠A

∠B = ∠Q

Therefore ,

BC / QR = AC / PR = AB / PQ

ar( ∆ABC) / ar(∆PQR ) = AB² / PQ² = 4 / 400 = 1/100