∆ ABC ∼ ∆ PQR such that ar (∆ ABC) = 4 ar (∆ PQR). Find QR, if BC = 12 cm.
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So answer is 3 cm.here h represent height.
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Answered by
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GIVEN: ΔABC~ΔPQR
[ar ΔABC] = 4[ar ΔPQR]
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