ΔABC ~ ΔPQR such that area (ΔABC) = 4area (ΔPQR). If BC = 12 cm, then QR =
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48 mulitiply
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We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding sides.
∴ar(ΔPQR)ar(ΔABC)=QR2BC2⇒12164=(15.4)2BC2
⇒118=15.4BC
⇒BC=118×15.4=11.2cm
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