Question

ΔABC right angled at B. AB=7, (AC-BC) = 1 cm (SecC+cotA)​

Answer 1

Answer:

The answer was in the photo

Answer 2

Given:

AB=7, (AC-BC) = 1 cm

To find:

(SecC+cotA)​

Solution:

1) InΔABC by the Pythagoras theorem

• AB²+BC²=AC²

• 7²+x²= (x+1)²

• 49+ x² = x²+1+2x

• 2x = 48

• x = 24

• BC = 24 cm

• AC = 1+x = 25 cm

2)According to the question,

• SecC + CotA

• AC/BC+ AB/BC

• 25/24 + 7/24

• 32/24

• 4/3

• 1.33

the value of (SecC+cotA)​ is 1.33